#Calc 3 spherical coords fins phi full#

Naturally, you could also use theta=0.2*Pi for full polar rotation. plot3d(cos(phi)/sin^2(phi),īut what you are looking for is the calling sequence where phi is the azimuthal angle, and so the calling sequence could be, plot3d(cos(phi)/sin(phi)^2,

In both of these phi is taken as the polar angle, and theta as the azimuthal angle. These two produce a similar result (yours is the first, for which Maple fills in the second range for you). Find an equation in rectangular coordinates for the equation given in spherical coordinates: /6 / 6. Maple is happy to provide the second for you, and it interprets the one you supplied as denoting the polar angle which comes first in this calling sequence. You only passed a single variable=range option to the plot3d command, and omitted the second. It doesn't distinguish them by any special naming convention. Maple distinguishes between the polar angle variable and the azimuthal angle variable by relative position in the calling sequence of the plotting command. You can use any names you want for the polar angle and the azimuthal angle. It doesn't distinguish between, say phi and theta by name. The plot3d command doesn't care what names you use for the plotting variables. This is the reason why we need to find du. In fact, the first part 0, 0.5 is actually contracted. We can see that there is stretching of the interval. The angles and are given in radians and degrees. This substitution sends the interval 0, 2 onto the interval 0, 4. You may also change the number of decimal places as needed it has to be a positive integer. 1 - Enter x x, y y and z z and press the button 'Convert'. You have overlooked the 2nd plotting variable. Use Calculator to Convert Rectangular to Spherical Coordinates. How come plotting the implicit equation differs from plotting the equation where I cancel one of the $ ho$ terms? Note that I obtain what looks like a correct result when I use the command implicitplot3d: implicitplot3d(rho*cos(phi) = rho^2*sin(phi)^2, rho = 0. Is there a mathematical mistake in my equation for a paraboloid, or is this a Maple-related issue? The Maple command I run is roughly plot3d(cos(phi)/sin^2(phi), phi=0.Pi/2, coords=spherical) When I try to plot this in Maple, I obtain a figure which does not correspond to a paraboloid. So here is what I believe the equation is in spherical coordinates Here is the equation of a paraboloid in rectangular coordinates

Calc 3 spherical coords fins phi